Answer:
The experiment report is a detailed discussion of the methodology followed in the experiment.How to write summary of experiment resultsAfter carrying out a laboratory experiment it is often expedient to write a summary of the experiment usually for the purpose of assessment by the instructor.Such reports begin with the title of the experiment followed by the material used in the experiment. Next comes the procedure of the experiment where all the details of the experiment are spelt out in detail.Lastly, you can now write the conclusion and the results obtained from the experiment in the last paragraph of the report.
Explanation:
The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C
<h3>How to calculate temperature?</h3>
The initial temperature of the copper metal can be calculated using the following formula on calorimetry:
Q = mc∆T
mc∆T (water) = - mc∆T (metal)
Where;
- m = mass
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:
400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)
30,096 = 93.6T - 2246.4
93.6T = 32342.4
T = 345.5°C
Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.
Learn more about temperature at: brainly.com/question/15267055
Answer:
1.48 x 10^47 mol of Na
Explanation:
8.90 x 10^24 atoms of Na (1 mol of Na/6.022 x 10^23 atoms of Na)=
1.48 x 10^47 mol of Na
CaCl2 + H2O are produced when HCl react with Ca(OH)2
Explanation
equation for reaction is as follows
Ca(OH)2 + 2HCl → CaCl2 +2H2O
1 mole of calcium hydroxide (Ca(OH)2 reacted with 2 moles of hydrochroric acid (HCl) to form 1 moles of calcium chloride CaCl2 and water H2O. This type of reaction is known as neutralization reaction since it between an acid (HCl) and a base (Ca(OH)2
