Solve the right angle trig. round to the nearest tenth.

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

x ≈ 16.5

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Geometry

[Right Triangles Only] cos∅ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

We are given a right triangle. We can use trig to find the missing side length.

Step 2: Identify Variables

POV from the angle

Angle = 38°

Adjacent Leg = x

Hypotenuse = 21

Step 3: Solve for x

Substitute [cosine]: cos38° = x/21
Isolate x: 21cos38° = x
Evaluate: 16.5482 = x
Rewrite: x = 16.5482
Round: x ≈ 16.5

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Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y = 8x - 6.

White raven [17]

Answer:

y = -0.25x + 2.25

Step-by-step explanation:

First, you can simplify the equation of the line it's perpendicular to (2y = 8x - 6) by dividing both sides by 2. This means you would get y = 4x - 3. From that you can conclude that the slope of that line is 4.

Lines always have a slope that is the negative reciprocal of the slope of the line they are perpendicular to, so you know the slope of the line is going to be -1/4.

So far, you have the equation y = -1/4x + b and you have to find b.

You can substitute in the point (-3, 3) so you would have 3= -1/4 * -3 + b

Solving,

3 = 3/4 + b

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3 years ago

Determine whether each table below models a linear, quadratic or exponential function.

Virty [35]

The correct answers are:

The first table is linear.
The second table is exponential.

Explanation:

To see if a set of data is linear, we find the slope. Slope is given by the formula

$m=\frac{y_2-y_1}{x_2-x_1}$ .

We check each pair of points in the first table. The slope between the first two points is:
$m=\frac{1-4}{6-5}=\frac{-3}{1}=-3.$

The slope between the second two points is:
$m=\frac{-2-1}{7-6}=\frac{-3}{1}=-3$

The slope between the third two points is:
$m=\frac{-5--2}{8-7}=\frac{-5+2}{8-7}=\frac{-3}{1}=-3$

Since the slope is the same between any two pairs of points, this is a linear set of data.

Checking each pair of points in the second table, we have:
$m=\frac{1-0}{6-5}=\frac{1}{1}=1$ for the first two points.

For the second pair of points, we have:
$m=\frac{4-1}{7-6}=\frac{3}{1}=3$

Since the slope is not the same between each pair of points, we know the data is not linear.

Next we will check the second table to see if it is quadratic. Since the x-coordinates go up the same number each time, we can check the y-coordinates, specifically looking at the second differences.

For the second differences, we first find the difference between each y-value:
1-0=1
4-1=3
8-4=4

Now we find the difference between each first difference:
3-1=2
4-3=1

Since these second differences are not the same, the data is not quadratic.

From graphing the data in the table, we can see that the data in the second table is exponential.