Question

Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y = 8x - 6.

Answer 1

Answer:

y = -0.25x + 2.25

Step-by-step explanation:

First, you can simplify the equation of the line it's perpendicular to (2y = 8x - 6) by dividing both sides by 2. This means you would get y = 4x - 3. From that you can conclude that the slope of that line is 4.

Lines always have a slope that is the negative reciprocal of the slope of the line they are perpendicular to, so you know the slope of the line is going to be -1/4.

So far, you have the equation y = -1/4x + b and you have to find b.

You can substitute in the point (-3, 3) so you would have 3= -1/4 * -3 + b

Solving,

3 = 3/4 + b

b = 2 and 1/4

Therefore the equation is y = -1/4x + 2 1/4 or y = -0.25x + 2.25