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mote1985 [20]
3 years ago
8

Please help me of this !! :))

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer: b

Step-by-step explanation:

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Factor completely 3X^2 -25​
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So, in this case, we're looking for the solutions of

3x^2-25=0 \iff 3x^2=25 \iff x^2 = \dfrac{25}{3} \iff x=\pm\sqrt{\dfrac{25}{3}}=\pm\dfrac{5}{\sqrt{3}}

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VLD [36.1K]
Hi,
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x^2-2x=10\\&#10;x^2-2x+1=10+1\\&#10;&#10;\Rightarrow\ (x-1)^2=11\\&#10;\Rightarrow\ (x-1)^2-11=0\\&#10;\Rightarrow\ (x-1)^2-( \sqrt{11})^2=0\\&#10;\Rightarrow\ ((x-1)+ \sqrt{11})((x-1)- \sqrt{11})=0\\&#10;\Rightarrow\ x-1+ \sqrt{11}=0\ or\ x-1- \sqrt{11}=0\\&#10;&#10;\Rightarrow\ x=1- \sqrt{11}\ or\ x=1+ \sqrt{11}\\&#10;&#10;&#10;&#10;
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Sholpan [36]

<em>The measure of PQ is 12.72</em>

<h2>Explanation:</h2>

We have the right triangle ΔPQR and we want to know the measure of PQ. PQ is opposite to ∠R, so from trigonometry we know that:

sin(\alpha)=\frac{Opposite \ side}{Hypotenuse} \\ \\ \\ Here: \\ \\ \alpha=m\angle R=58^{\circ} \\ \\ Opposite \ side=\overline{PQ} \\ \\ Hypotenuse=\overline{RQ}=15 \\ \\ \\ So: \\ \\ sin(58^{\circ})=\frac{\overline{PQ}}{15} \\ \\ \\ Isolating \ \overline{PQ}: \\ \\ \overline{PQ}=15sin(58^{\circ}) \\ \\ \overline{PQ}=15(0.848)\\ \\ \boxed{\overline{PQ}=12.72}

<h2>Learn more:</h2>

Right triangles: brainly.com/question/10252821

#LearnWithBrainly

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