All categories

2 years ago

Can you answer this quick it's so hard

Mathematics

2 answers:

bulgar [2K]2 years ago

7 0

1. The shape of the base is a square.

2. The lateral faces are triangles.

3. Including the square and four triangles, the figure has 5 faces.

4. Square pyramid.

5. Find the surface area of the square. Find the surface area of one triangle, and multiply by 4 to get all of them. Add the area of the four triangles to the area of the square.

Hope this helps.

Bingel [31]2 years ago

6 0

Answer:

square

triangle

square pyramid

find area of base and area of a lateral face (base is 1 side squared, lateral face is base * height / 2. Multiply area of lateral face by 4 and add the product to the area of the base to find the Surface Area.

Step-by-step explanation:

You might be interested in

Aida applied the distributive property to write the equivalent expressions below.

morpeh [17]

Answer:

The answer is b

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. It goes through poi

iVinArrow [24]

Answer:

y=100* $0.6^{x}$

Step-by-step explanation:

7 0

3 years ago

The population of a strain of bacteria doubles in a culture. At noon there were 80 bacteria present and by 4:00 PM there were 20

Nastasia [14]

Answer:

t = 1/2 hour

Step-by-step explanation:

20480 = 80 $x^{t }$

20480 = 80 $x^{4 }$

20480/80 = $x^{4 }$

256 = $x^{4 }$

x = 4

doubling period

2 = $4^{t}$

t = 1/2 hour

3 0

2 years ago

Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.

Over [174]

Solution:

Formula for radioactive Decay is given by

$R_{0}= R(1-\frac{S}{100})^t$

$R_{0}$ = Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

$72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64$ →→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

$15=(15+k)(1-\frac{35}{100})^{3.64+t}$ →→→ Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.