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Karolina [17]
3 years ago
15

Find the length s of the arc of a circle of radius 20 miles subtended by the central angle 33º

Mathematics
1 answer:
AysviL [449]3 years ago
6 0
Arc length is figured by the following formula theta/360 x 2pi(r) input the knowns 30/360x2pi(20)=11.52 miles
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The Law of Large Numbers: I need help on finding the probability of this situation.
Stella [2.4K]

The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes for the bus to get to school is 20 minutes (with a standard deviation of 4 minutes). The distributions are normal. a. How long will it take (in minutes), on average, to get to school? b. What is the standard deviation of the trip to school? c. What is the probability that it will take longer than 30 minutes to get to school? Due to a miscalculation, you realize it actually takes an average of 10 minutes to walk to the bus stop. d. How long will it take (in minutes), on average, to get to school? e. What is the standard deviation of the trip to school? f. What is the probability that it will take longer than 30 minutes to get to school? The only ones I need help with is C and F. I have the answer for the rest of them. Can someone please help me with parts C and F??

4 0
3 years ago
Pedro gets 8 hours of sleep each night.how many hours does pedro sleep in a year with 365 days
stepladder [879]
365 times 8 = 2920 hr of sleep in a year 
6 0
3 years ago
Read 2 more answers
Start with the geometric power series LaTeX: 1+x+x^2+x^3+x^4+\cdots Substitute LaTeX: -x^3in place of LaTeX: x, and then take a
valina [46]

Answer:

-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}

Step-by-step explanation:

Given : 1+x+x^2+x^3+x^4+\cdots

On putting -x^3 in place of x , we get 1+\left ( -x^3 \right )+\left ( -x^3 \right )^2+\left ( -x^3 \right )^3+\left ( -x^3 \right )^4+...

On simplifying , we get 1-x^3+x^6-x^9+x^{12}+...

On differentiating , we get \left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...

Here ,

-3x^2=\left ( -1 \right )^1\,3(1)x^{3(1)-1}\\6x^5=\left ( -1 \right )^2\,\,3(2)\,\,x^{3(2)-1}\\-9x^8=\left ( -1 \right )^3\,\,3(3)\,\,x^{3(3)-1}\\12x^{11}=\left ( -1 \right )^4\,\,3(4)\,\,x^{3(4)-1}

Now , we need to express it using summation notation.

\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}

4 0
3 years ago
15 points! whats value of q?
Dafna1 [17]

Answer:

30 degrees

Step-by-step explanation:

Good luck fam

5 0
3 years ago
Which is the equation of a parabola with vertex (0, 0), that opens downward and has a focal width of 6?​
Deffense [45]

Answer:Ambitious

Vertex: V=(0,0)=(h,k)→h=0, k=0

Opens downward:

(x-h)^2=4p(y-k)

Width focal: p=-6<0 (donwnward)

Replacing h=0, k=0 and p=-6 in the equation above:

(x-0)^2=4(-6)(y-0)

x^2=-24y

Answer: The equation of the parabola is  x^2=-24y

7 0
3 years ago
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