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3 years ago

The value of the expression -2 xy for x = -4.7 and y = 0.2 is _____.

Mathematics

2 answers:

sergeinik [125]3 years ago

4 0

The value of the expression -2xy for x = -4.7 and y = 0.2 is 1.88. Thus option number 3 is correct.

Solution:

We have been given an expression that is -2xy and have been asked to find its value for the given values of x and y

The given values of x and y are -4.7 and 0.2 respectively.

To find the value of the expression for the given values of x and y we substitute the values of x and y in the given expression and solve it as follows:

Given expression = -2xy

$\begin{array}{l}{=-2(-4.7)(0.2)} \\\\ {=9.4 \times 0.2} \\\\ {=1.88}\end{array}$

Hence the option number 3 is correct.

Verdich [7]3 years ago

4 0

hello!

option 3, 1.88

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2 years ago

A quarter back is sacked for a loss of 4 yards. On the next play his team loses 10 yards. Then the team gains 12 yards on the th

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Answer:

see below

Step-by-step explanation:

loss of 4 yards

-4

loses 10 yards.

-10

gains 12 yards

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The expression for the three plays

-4 +(-10) + 12

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2 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

Helga [31]

Answer:

$\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n$

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function f at the number a is:

$f(x) = \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n$

$f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ...$ ............ equation (1)

Now we will find the function f and all derivatives of the function f at a = -2

f(x) = 10/x f(-2) = 10/-2

f'(x) = -10/x² f'(-2) = -10/(-2)²

f"(x) = -10.2/x³ f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴ f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵ f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function f at a = -4 means that we substitute the value of each function into equation (1)

So, we get $\sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}}$ Or $\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n$

4 0

3 years ago

Need help please, does any one know how to do this

ziro4ka [17]

Answer:

(6-u)/(2+u)
8/(u+2) -1
-u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

(-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

(6 -u)/(u +2)

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

4) You can also multiply numerator and denominator by some constant, say 3:

-(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

(1+x^2)(6 -u)/((1+x^2)(u+2))

7 0

3 years ago

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kifflom [539]

option 3

they are corresponding angles and are congruent

8 0

3 years ago