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3 years ago

What is the slope of the line that passes through the points (6, -5) and (6, —8)?

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

6 0

Answer:

(y2 -y1) / (x2 - x1)

Step-by-step explanation:

use that formula. The answer should be -3/0 which doesn't make sense. Are you sure you have your x values correct? Since in that case it would be a straight line and the equation for that would be x = 6 since it is a straight line up with no y intercept.

Hope that helped

gogolik [260]3 years ago

5 0

Answer:

Undefined

Step-by-step explanation:

GIVEN :-

A line passes through two points , and their coordinates are given below :-

(x₁ , y₁) = (6 , -5)
(x₂ , y₂) = (6 , -8)

TO FIND :-

Slope of the line

FORMULAE TO KNOW BEFORE SOLVING :-

Lets say there's a line passing through (x₁ , y₁) & (x₂ , y₂).

$=> Slope \: of \: the \: line = \frac{Rise}{Run} = \frac{y_2 - y_1}{x_2 - x_1}$

SOLUTION :-

According to the question ,

$=> Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-8 -(-5)}{6 - 6} = \frac{-8 + 5}{0} = \frac{-3}{0}$ = undefined (∵ Anything divided by 0 is undefined.)

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Answer:

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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d

skelet666 [1.2K]

Answer:

$z=-0.842$

And if we solve for a we got

$a=30 -0.842*7.8=23.432$

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(30,7.8)$

Where $\mu=30$ and $\sigma=7.8$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.80$ (a)

$P(X$ (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

$P(X$