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Korolek [52]
3 years ago
10

After viewing the tutorial, open a spreadsheet in the Excel application and type the following data gathered from mass and volum

e data of different samples of an unknown metal.
Data Table of Mass and Volume for Unknown Metal

Enter "Volume (mL)" in column A and "Mass (g)" in column B

Volume (mL) Mass (g)
0.259 5.00
0.776 15.0
1.24 24.0
2.69 52.0
3.31 64.0
4.19 81.0
4.92 95.0
5.28 102.0
7.35 142.0
8.59 166.0

After the data is entered - follow the steps in the tutorial and you will have a graph that is professional in appearance.

Be certain that the following is included on your scatter plot (line graph). If not, go back to the graph and enter the missing information. The legend is not needed on this graph.
I NEED HELP ASAP
Chemistry
1 answer:
Anna [14]3 years ago
6 0

Answer:

wow this is an interesting question

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<span>1,3-cylohexadiene i synthesized starting from cyclohexane in following 4 steps.

1) Free Radical Substitution Rxn:
 Halogenation of cyclohexane in the presence of UV yield chlorocyclohexane.

2) Elimination Rxn: Dehydrohalogenation of chlorocyclohexane yields cyclohexene.

3) Halogenation of Cyclohexene (Electrophillic Addition Rxn) gives 1,2-dihalocyclohexane.

4) Elemination Rxn: When dibromocyclohexane is treated with KOH and heated it gives 1,3-cyclohexadiene as shown below,</span>

4 0
3 years ago
The balloon is removed from the freezer and returned to its initial conditions. It is then heated to a tempatuew of 2T at a pres
slavikrds [6]

Answer:

answer: It does not change

Explanation:

7 0
3 years ago
In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2
Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)

the enthalpy of reaction is given as  ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ

7 0
3 years ago
What factors help veins push blood back to the heart
Vladimir79 [104]
Contractions of the skeletal muscles
As it puts pressure and moves the blood along
5 0
3 years ago
A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm p
olchik [2.2K]

Answer:

299.14 K or 26°C

Explanation:

The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.

The ideal gas law is often written as

PV = nRT

where P ,V and T are the pressure, volume and absolute temperature;

n is the number of moles of gas and  R is the ideal gas constant.

n=1.10 x 10^5 mol  

V= 2.70 x 10^6 L  

P= 1.00 atm= 101.325 kPa  

R= 8.314 kPa*L/ mol*K

when the formula is  rearranged, T=PV/ nR  

T = (101.325kPa * 2.70 x 10^6 L)/ (1.10 x 10^5 mol * 8.314 kPa*L/ mol*K)  

T = 299.1421917 K

or

T = 299.14 - 273.15 = 25.99 =  26°C

4 0
3 years ago
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