Bc the number of protons & electrons are the same but the number or neutrons are changed
Example #1 write the chemical formula for Calcium Oxide
Step 1
-Find the Atomic symbol of the metal and non-metal on the periodic table
CaO
Step 2
Find the charges for Calcium and Oxygen
which are Ca 2+ and O 2-
Step 3
Balance out the charges
They are already balanced out
Here´s the chemical formula for Calcium Oxide
CaO
Example 2 write the chemical formula for Aluminum Oxide
Step 1
-Find the Atomic symbol of the metal and non-metal on the periodic table
A
l
O
Step 2
Find the charges for Aluminum and Oxygen
Which are Al 3+ and O 2-
Step 3
Balance out the charges
You need 2 Aluminum and 3 Oxygen to balance the charges
Al 3+ O 2-
Al 3+ O 2-
= 6 + O 2-
= 6-
Step 4
If you need more then one element to balance out the charges you identify that by using subscripts
Heres your chemical formula for Aluminum Oxide

Answer:
67.5 atm
Explanation:
To answer this problem we can use <em>Boyle's law</em>, which states that at constant temperature the pressure and volume of a gas can be described as:
P₁V₁=P₂V₂
In this case:
P₁ = 101.3 atm
V₁ = 0.500 L
P₂ = ?
V₂ = 0.750 L
We input the data:
101.3 atm * 0.500 L = P₂ * 0.750 L
And solve for P₂:
P₂ = 67.5 atm
<span>5.75 moles
The formula for methyl tert-butyl ether is (CH3)3COCH3, so a single molecule has 5 carbon, 12 hydrogen, and 1 oxygen atoms. So for every 12 moles of hydrogen, there's 1 mole of oxygen. So simply divide the number of moles of hydrogen by 12 to get the number of moles of oxygen.
69.0 / 12 = 5.75
Therefore there's 5.75 moles of oxygen in the sample.</span>
Answer: -1835 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
(1)
(2)
Net chemical equation:
(3)
Multiplying equation (1) by 4, and reversing we get
(4)
Adding (2) and (4)
Thus enthaply change for the reaction is -1835 kJ.