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sasho [114]
3 years ago
14

Which of the following is true of science? (2 points)

Chemistry
1 answer:
yulyashka [42]3 years ago
5 0

Body of knowledge gained using inquiry and expirimentation

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Hydrogen peroxide (h​2​o​2​) decomposes according to the equation:h​2​o​2​(​l​) ​⇆​ h​2​o(​l​) + ½ o​2​(​g​)calculate k​p​ for t
goldenfox [79]
Hello! Let me try to answer this :)

Thanks and please correct if there are any mistakes ^ ^

6 0
3 years ago
You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution
LUCKY_DIMON [66]

<u>Answer:</u> The mass of solution having 768 mg of KCN is 426.66 grams.

<u>Explanation:</u>

We are given:

0.180 mass % of KCN solution.

0.180 %(m/m) KCN solution means that 0.180 grams of KCN is present in 100 gram of solution.

To calculate the mass of solution having 768 mg of KCN or 0.786 g of KCN   (Conversion factor:  1 g = 1000 mg)

Using unitary method:

If 0.180 grams of KCN is present in 100 g of solution.

So, 0.768 grams of KCN will be present in = \frac{100g}{0.180g}\times 0.768=426.66g of solution.

Hence, the mass of solution having 768 mg of KCN is 426.66 grams.

8 0
3 years ago
Which observation could you make based on stimuli to your photoreceptors?(1 point)
Montano1993 [528]

Answer:

last one which is d

Explanation:

thankskd

6 0
3 years ago
Electrophilic addition of hbr to 3-methyl-2-hexene creates an asymmetric center at c-2. what is the product of this reaction?
AleksandrR [38]

This reaction would give rise to two products.

  • 2-bromo-3-methylhexane, and
  • 3-bromo-3-methylhexane.

However, 2-bromo-3-methylhexane would be more common than 3-bromo-3-methylhexane among the products.

The hydrogen atom in a hydrogen bromide molecule carries a partial positive charge. It is attracted to the double bond region with a high electron density. The hydrogen-bromine bond breaks when HBr gets too close to a double bond to produces a proton \text{H}^{+} and a bromide ion \text{Br}^{-}.

The proton would attack the double bond to produce a carbocation. It could attach itself to either the second or the third carbon atom.

  • \phantom{\text{H}_3\text{C}-\text{CH}-\;}+\\\text{H}_3\text{C}-\text{CH}-\text{CH}-\text{CH}_2-\text{CH}_2-\text{CH}_3\\\phantom{\text{H}_3\text{C}-\;\;}|\phantom{\text{CH}-}\;}|\\\phantom{\text{H}_3\text{C}-\;} \text{H}\phantom{\text{CH}}\;\;}\text{CH}_3
  • \phantom{\text{H}_3\text{C}-\text{CH}-}\;\;\text{H}\\\phantom{\text{H}_3\text{C}-\;}+\phantom{\text{H}-\;}|\\\text{H}_3\text{C}-\text{CH}-\text{CH}-\text{CH}_2-\text{CH}_2-\text{CH}_3\\\phantom{\text{H}_3\text{C}-\;\;\;}\phantom{\text{CH}-}\;}|\\\phantom{\text{H}_3\text{C}-\;} \phantom{\text{H}}\phantom{\text{CH}}\;\;}\text{CH}_3

Carbocations are unstable and might decompose over time. The first carbocation is more stable than the second for having three alkyl groups- i.e., straight carbon chains- attached to the center of the positive charge. Alkyl groups have stabilizing positive induction effect on positively-charged carbon.   The second carbocation has only two, and is therefore not as stable. The first carbocation thus has the greatest chance to react with a bromide ion to produce a stable halocarbon.

Bromide ions are negatively charged. They attach themselves to carbocations at the center of positive charge. Adding a bromide ion to the first carbocation would produce 3-bromo-3-methylhexane whereas adding to the second produces 2-bromo-3-methylhexane.

The <em>most likely</em> product of this reaction is therefore 3-bromo-3-methylhexane.

6 0
3 years ago
How many grams of water vapor (H2O) are in a 10.2-liter sample at 0.98 atmospheres and 26°C?
diamong [38]
Hey there! 

<span>Use the equation of Clapeyron:
</span>
T in kelvin :

26 + 273.15 => 299.15 K

R = 0.082

V = 10.2 L

P = 0.98 atm

number of moles :

P *V = n * R * T

0.98 * 10.2 =  n * 0.082 * 299.15

9.996 = n * 24.5303

n = 9.996 / 24.5303

n = 0.4074 moles

Therefore:

Molar mass H2O = 18.01 g/mol

1 mole H2O ------------- 18.01 g
0.4074  moles ----------- m

m = 0.4074 * 18.01 / 1

m = 7.339 g of H2O
5 0
3 years ago
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