At constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
<h3>
Boyle's law</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
- Initial volume of the gas V₁ = 30.0mL = 0.03L
- Initial pressure of the gas P₁ = 1.53atm
- Final volume of the gas V₂ = 50.1mL = 0.0501L
- Final pressure of the gas P₂ = ?
We substitute our given values into the expression above to determine the new pressure.
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.53atm × 0.03L ) / 0.0501L
P₂ = 0.0459Latm / 0.0501L
P₂ = 0.92atm
Therefore, at constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
Learn more about Boyle's law here: brainly.com/question/1437490
Answer:
Option (B) is correct.
Explanation:
Initial temperature of the gas is T.
The volume of the sample is decreased from 4.5 L to 1.5 L while the pressure is held constant.
At constant pressure, the relation between volume and temperature is given by :

Here, V₁ = 4.5 L, V₂ = 1.5 L, T₁ = T₁, T₂ = ?
So,

So, the final temperature of the gas is
. Hence, the correct option is (B).
Answer is: 28 kJ.
Chemical reaction: A₂ + B₂ ⇄ 2AB.
Ea(forward) = 105 kJ/mol.
Ea(reverse) = 77 kJ/mol.
ΔH(reaction) = ?
<span>The enthalpy change of reaction is the change in the energy of the reactants to the products.
</span>ΔH(reaction) = Ea(forward) - Ea(reverse).
ΔH(reaction) = 105 kJ/mol - 77 kJ/mol.
ΔH(reaction) = 28 kJ/mol; this is endothermic reaction (ΔH <span>> 0).</span>
The answer is, All of the above