Answer:
Margin of error for a 95% of confidence intervals is 0.261
Step-by-step explanation:
<u>Step1:-</u>
Sample n = 81 business students over a one-week period.
Given the population standard deviation is 1.2 hours
Confidence level of significance = 0.95
Zₐ = 1.96
Margin of error (M.E) = 
Given n=81 , σ =1.2 and Zₐ = 1.96
<u>Step2:-</u>
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On calculating , we get
Margin of error = 0.261
<u>Conclusion:-</u>
Margin of error for a 95% of confidence intervals is 0.261
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Answer:

Step-by-step explanation:
Given


Required
Determine LN
Since LM is a bisector, then we have:
(See attachment for illustration)

Collect Like Terms


Solve for w


LN is calculated as thus:

Substitute 4 for w



Answer: x= 2.5, y = 10
Step-by-step explanation:
<u><em>I'm going to assume that these photocopies are proportional in relations to each other.</em></u>
If they're proportional, you can set up two proportions:

And cross-multiply:

Then solved for x and y:

The answer is 6x + 0.50x= 2.50