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Nataly [62]
3 years ago
11

Which operation would help solve for w?

Mathematics
1 answer:
Vilka [71]3 years ago
6 0

Answer:

B. Divide each side by 8

Step-by-step explanation:

Here is how:

8w ÷ 8 = 72 ÷ 8

w = 72 ÷ 8

w = 9

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Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
-2 (z + 11) = 6<br><br> Please help. You have to use distributive property.
Mamont248 [21]

Answer:

-14

Step-by-step explanation:

-2(z+11)=6

-2z-22=6

-2z=28

z=-14

4 0
2 years ago
3/15 + 9/15 + 26/15=
klasskru [66]

Answer:

Mixed number - 2 8/15

decimal - 2.53

Step-by-step explanation:

3+9+26=38

denominator is 15

38/15 convert to a mixed number =

2 8/15  as a decimal is 2.53

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3 years ago
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