Complete question :
Cheddar Cheese
$3/lb
Swiss Cheese
$5/lb
Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Answer:
10 lbs of cheddar cheese
6 lbs of Swiss cheese
$3a + $5b = $30
Step-by-step explanation:
Given that :
Cheddar cheese = $3/lb
Swiss cheese = $5/lb
Total amount budgeted for cheese = $30
How many pounds of cheese can Keisha get if she buys only Cheddar cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of cheddar cheese
$30 / 3 = 10 pounds of cheedar cheese
Only Swiss cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of Swiss cheese
$30 / 5 = 6 pounds of Swiss cheese
A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Let amount of cheddar cheese she can get = a
Let amount of Swiss cheese she can get = b
Hence,
(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount
(3 * a) + (5 * b) = $30
$3a + $5b = $30
The answer is 3.4, you need to subtract 1.6 from 5.
Answer:
Step 2 is wrong.
It should be 3x – <u>18</u> + 4x + 12 – 6x
Explanation:
3(x – 6) + (4x + 12) – 6x →
3x – 18 + 4x + 12 – 6x →
(3x + 4x – 6x) + (-18 + 12) →
x – 6
Answer:
-2 =m
Step-by-step explanation:
–15 = 4m – 7
Add 7 to each side
–15+7 = 4m – 7+7
-8 = 4m
Divide each side by 4
-8/4 = 4m/4
-2 =m
Answer:
![2xyzx^{2} \sqrt[ 0]{xyz}](https://tex.z-dn.net/?f=2xyzx%5E%7B2%7D%20%5Csqrt%5B%200%5D%7Bxyz%7D)
Step-by-step explanation:
simplify the radical by breaking the radicand up into a product of know factors
