8-9 8-19 ................................
First you have to solve for x and y and when you have you points then plot them
9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
143π in³
Step-by-step explanation:
A basketball has the shape of a sphere
Volume of a basketball = 4/3πr³
Diameter = 9.5 in
Radius = diameter/2
= 9.5/2
= 4.75 in
Volume of a basketball = 4/3πr³
= 4/3 * π * 4.75³
= 4/3 * π * 107.17
= (4*π*107.17) / 3
= 428.68π / 3
= 142.89π in³
Approximately
143π in³ to the nearest whole number
