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3 years ago

Can someone help me with explaining this question? Or explain to me if my choice is wrong? Thanks It is math, attachment below

Mathematics

1 answer:

vitfil [10]3 years ago

4 0

Answer:

the answer is True (explanation below) your current answer is incorrect the equation does have No Solution.

Step-by-step explanation:

The equation has no solution because when you simplify the equation as much as possible, we are left with 2=-2. However, 2=-2 is not true, so there is no answer to this equation.

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Sergio [31]

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3 years ago

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Please help me I need help with my test review I can’t figure out m<1 and m<2

aksik [14]

Answer:

m1=12 and m2=168

Step-by-step explanation:

$m1 + m2 = 180 \: (straight \: angle) \\ then \\ x - 12 + 7x = 180 \\ 8x - 12 = 180 \\ 8x = 180 + 12 = 192 \\ x = 192\div 8 \\ x = 24\\ hence \\ m1 = 24 - 12 = 12 \\ m2 = 7 \times 24 = 168.$

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4 years ago

If 9 : x= x4. then x= _____.<br>a) 36<br>b) 18<br>c) 24<br>d) 6

cupoosta [38]

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3 years ago

A sports club has 84 members who learned baseball, and 42 of those members also learned basketball. There are 25 students who di

HACTEHA [7]

<em>The table that shows the relative frequency of data is in the below further explanation.</em>

$\texttt{ }$

<h3>Further explanation</h3>

A set is a clearly defined collection of objects.

To declare a set can be done in various ways such as:

With words or the nature of membership

With set notation

By registering its members

With Venn diagrams

$\texttt{ }$

Multiplying set A x B is by pairing each member of set A with each member of set B.

<u>Example:</u>

Then

A x B = {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)}

$\texttt{ }$

Union of set A and B ( A ∪ B ) is rewriting each member A and combined with each member B.

Intersection of set A and B ( A ∩ B ) is to find the members that are both in Set A and Set B.

<u>Example:</u>

A ∪ B = {1, 2, 3, 4, 5}

A ∩ B = {3, 4}

Let us now tackle the problem!

$\texttt{ }$

<em>A sports club has 84 members who learned baseball, and 42 of those members also learned basketball.</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{42}& \\Don't Play Basketball& & \end{array}\right]$

$\texttt{ }$

Number of members who learned baseball but did not learn basketball will be ( 84 - 42 ) = 42 members

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42& \\Don't Play Basketball&\boxed{42}& \end{array}\right]$

$\texttt{ }$

<em>There are 25 students who did not learn baseball but learned basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&\boxed{25} \\Don't Play Basketball&42& \end{array}\right]$

$\texttt{ }$

<em>8 students did not learn either baseball or basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&25 \\Don't Play Basketball&42&\boxed{8} \end{array}\right]$

$\texttt{ }$

<em>Total Number of Students = 42 + 42 + 25 + 8 = 117</em>

$\texttt{ }$

Table of relative frequency

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{25}{117}} \\Don't Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{8}{117}} \end{array}\right]$