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3 years ago

How do you work out these questions???????????

Mathematics

1 answer:

umka2103 [35]3 years ago

4 0

Divide the first one to 2 rectangles by drawing a line and then find the area of both rectangles, then add them.

The second one is divided in to 2 trapezoids. Find the area of both trapezoids and then add them.

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3x + 45= 60 solve for x

dedylja [7]

Answer:

x=5

Step-by-step explanation:

3x + 45 = 60

-45 -45

3x = 15

15 ÷ 3= 5

x= 5

-I hope this helps have a great day!

8 0

3 years ago

A(n)=−5+6(n−1)<br> What is the 12th term in the sequence

barxatty [35]

Answer:

n/2[2a+(n-1)d]

12/2[2(-5)+(12-1)6]

66-10=56×6=336

336 is the 12th term

4 0

2 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

2 years ago

Evaluate-(3^5)(3^3) <br>

Stells [14]

Answer:

(3+(3)/(5))(3-(3)/(5))

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What are the possible rational zeros of f(x)=x^4+2x^3-3x^2-4x+20?

Mice21 [21]

Roots test tells us to take the factors of the 20 divided by the factors of the coefficient of the the first.

factors of 20 are 1,2,4,5,10,20
factors of 1 are 1

so plus or minus 1/1, 2/1, 4/1, 5/1, 10/1, 20/1 are all possible rational zeros

8 0

3 years ago