Answer: the cost of one chicken is $8
The cost of one duck is $5
Step-by-step explanation:
Let x represent the cost of one chicken.
Let y represent the cost of one duck.
Last month, he sold 50 chickens and 30 ducks for $550. It means that
50x + 30y = 550- - - - - - - - - - - 1
This month, he sold 44 chickens and 36 ducks for $532. It means that
44x + 36y = 532- - - - - - - - - - - 2
Multiplying equation 1 by 44 and equation 2 by 50, it becomes
2200x + 1320y = 24200
2200x + 1800y = 26600
Subtracting, it becomes
- 480y = - 2400
y = - 2400/- 480
y = 5
Substituting y = 5 Intl equation 1, it becomes
50x + 30 × 5 = 550
50x + 150 = 550
50x = 550 - 150
50x = 400
x = 400/50
x = 8
Answer:
7/13
Step-by-step explanation:
P(A or B) = P(A) + P(B) − P(A and B)
P(red or jack) = P(red) + P(jack) − P(red and jack)
P(red or jack) = 26/52 + 4/52 − 2/52
P(red or jack) = 28/52
P(red or jack) = 7/13
2x + y = 5
Put the coordinates of the points to the equation and check it:
A. 5 - not make sense
B. (1, 2) - x = 1, y = 2
2(1) + 2 = 2 + 2 = 4 ≠ 5 NOT
C. (2, -1) - x = 2, y = -1
2(2) + (-1) = 4 - 1 = 2 ≠ 5 NOT
D. (3, -1) - x = 3, y = -1
2(3) + (-1) = 6 - 1 = 5 YES
<h3>Answer: D. (3, -1).</h3>
Four plus the absolute value of twenty-seven minus ten
D = 2C
J = 1/3D
J = C - 1
J = 1/3D
J = 1/3(2C)
J = 2/3C
2/3C = C - 1
2/3C - 3/3C = -1
-1/3C = -1
C = -1 * -3
C = 3...there are 3 cats
J = C - 1
J = 3 - 1
J = 2.....there are 2 collars
