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zimovet [89]
3 years ago
5

There are 600 performers in a dance recital. The ratio of men to women is 4:6. How many men performers were in the dance recital

Mathematics
1 answer:
posledela3 years ago
5 0

Answer: 240 men

Step-by-step explanation:

From the question, we are informed that there were 600 performers in a dance recital and that the ratio of men to women is 4:6.

Fraction of men at the recital = 4/10

Fraction of women at the recital = 6/10

The number of men performers that were in the dance recital will be:

= 4/10 × 600

= 240 men

There were 240 men at the recital.

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Answer:

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Step-by-step explanation:

As we know ,

Sum of supplementary angles is 180 degrees.

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∠G + ∠H = 180

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<h3>How to determine the number of real zeros?</h3>

The equation of the function is given as:

f(x) = x^3 + 4x^2 + x - 6

Expand the function

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Reorder the terms

f(x) = x^3 + 5x^2 + 6x - x^2 - 5x - 6

Factor the expression

f(x) = x(x^2 + 5x + 6) -1(x^2 + 5x + 6)

Factor out x -1

f(x) = (x^2 + 5x + 6)(x -1)

Expand

f(x) = (x^2 + 3x + 2x + 6)(x -1)

Factorize

f(x) = [x(x + 3) + 2(x + 3)](x - 1)

Factor out x + 2

f(x) = (x + 3)(x + 2)(x- 1)

The function has been completely factored and it has 3 linear factors

Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

Read more about functions at:

brainly.com/question/7784687

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Step-by-step explanation:

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