Answer:
im in k12, hello and how are you on this fine day? :D
Step-by-step explanation:
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
The answer is
27/5 = 5 2/5 = 5.4
ANSWER:
According to question, our g(x) becomes f(x) - 5.
When x = 1,
f(x) - 5 = 5 - 5 = 0.
When x = 2,
f(x) - 5 = 7 - 5 = 2.
When x = 3,
f(x) - 5 = 11 - 5 = 6.
When x = 4,
f(x) - 5 = 19 - 5 = 14.
So, <u>Correct choice</u> - [D]
