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tensa zangetsu [6.8K]
4 years ago
15

How do you solve 3,4,and 5?

Mathematics
2 answers:
vodomira [7]4 years ago
4 0

3. Is number of tables times 5 so 2*5

So answer would be 10 15 20 25

Aleksandr [31]4 years ago
4 0
On 2 is 10 on 3 is 15 on four is 20 and five is 25
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Answer:

193

Step-by-step explanation: 40x9

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3 years ago
PLEASE HELP!!!!! I really need help with this.
____ [38]

Answer:

w = 4.66

Step-by-step explanation:

A . 4 =  18 - 3w

Transpose to find w

3w = 18 -4

3w = 14

w = 14 / 3

w = 4.66

8 0
3 years ago
Read 2 more answers
Find the missing side of this triangle, round to the nearest tenth if needed PLEASE HELP WILL MARK BRAINLIEST
serious [3.7K]

Answer:

The value of x:

  • x\:\approx \:8 in

Step-by-step explanation:

Given

b=4.8 in

c=9.3 in

a = x

we have to determine 'x'.

As the given triangle is a right-angled triangle.

Pythagorean Theorem:

For a right-angled triangle, with sides 'a' and 'b', the hypotenuse 'c' is defined as

c=\sqrt{a^2+b^2}

so

a=\sqrt{c^2-b^2}

as

  • b=4.8 in
  • c=9.3 in
  • a = x

substituting the values

x=\sqrt{9.3^2-4.8^2}

x\:\approx \:8 in

Thus, the value of x:

  • x\:\approx \:8 in
8 0
3 years ago
Tell whether a triangle can have sides with the given lengths explain? Explain. 4,7,10
Evgen [1.6K]
Use the pythagorean theorem. So 4^2 + 7^2 = 10^2. Simplify to 16+49=100. This simplifies to 65=100 which is not true so these sides cannot make a triangle.
4 0
4 years ago
Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
alukav5142 [94]

Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

Hence:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

Simplify:

\displaystyle =\lim_{x\to\infty}3=3

The limit of a constant is simply the constant.

We acquire the same answer.

6 0
3 years ago
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