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3 years ago

Pls help this is due in a little bit I don't wanna failllll

Mathematics

1 answer:

Fittoniya [83]3 years ago

6 0

The answer is 8 3/4. Hope this helps

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1 1/5 + 3 2/5 What’s the answer?????????

AURORKA [14]

Answer:

4 3/5

Step-by-step explanation:

1 1/5 + 3 2/5

=6/5+17/5

=（6+17）/5

=23/5

=4 3/5

7 0

3 years ago

Read 2 more answers

Solve for x: x + 4 = 15.25 1. x = 11.25 2. x = 19.25 3. x = 3.8125

allochka39001 [22]

X+4-4=15.25-4
X=11.25
Answer would be 1. X=11.25

4 0

3 years ago

A chair for an adult is 20 in. tall and 16 in. wide. A builder

Mashcka [7]

Answer:

4 in. wide

Step-by-step explanation:

20/5=4

4x=16

4x/4=16/4

x=4

3 0

3 years ago

<1 and <2 are complementary angles. the measure of <1 is 42°. The measure of <2 is 3x°. find the value of x.

jeka94

90-42=48

48=3x
48/3=16

x=17

6 0

3 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

1364 is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

1. 5 digit numbers:

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

2. 4 digit numbers:

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

3. 3 digit numbers:

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

4. 2 digit numbers:

We have 2 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

5. 1 digit numbers:

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = 1364

3 0

3 years ago