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3 years ago

Find a solution to the linear equation 6x+y=6

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

y = -6x + 6

Step-by-step explanation:

Unless you are asking for solving the linear equation itself, the answer would be y = -6x + 6.

If you were trying to set up systems and then solve for actual solutions, you would need two equations. I will go with solving the linear equation, but if you meant solving systems, the answer cannot be found.

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I’m the triangle shown below what is the approximate value of x

Dafna1 [17]

Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides $x,y$ and hypotenuse $z$ :

$x^2+y^2=z^2.$

In our case

$z=26$

$y=13$

So we solve for $x:$

$x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2} =\boxed{22.52\: units.}$

Which is choice B.

8 0

3 years ago

Solve: 1/5c =15 c=__ solve what c equals

grin007 [14]

Answer:

Step-by-step explanation:

a fifth of c is 15

75÷5=15

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3 years ago

(3x/5-7)+7 is equal to what

Elena L [17]

(3x/5-7)+7

= (3x/-2) + 7

= -3x/2 + 7

5 0

3 years ago

Do you always eat breakfast?

dybincka [34]

Answer:

unbias

Step-by-step explanation:

Not asking specific group or person.

3 0

3 years ago

Is -2 a solution to 4x^(3)-x^(2)+16x-4

sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for $x=-2$ to be a solution, the result after substituting must be 0:

$4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0$

$4(-8)-4-32-4\stackrel{?}{=}0$

$-32-40\stackrel{?}{=}0$

$-72\neq0$

Therefore, $x=-2$ is not a solution to $4x^3-x^2+16x-4$

3 0

2 years ago