Given:
Length of first vector = 2 meters
Length of second vector = 4 meters
To find:
The vector which has a greater magnitude.
Solution:
We know that, magnitude of a vector represents the length of it.
The first vector that is 2 meters long has a magnitude 2.
The second vector that is 4 meters long has a magnitude 4.
Clearly, 4 is greater that 2, i.e., 4 > 2. So, magnitude of second vector is greater.
Therefore, the vector that is 4 meters long has greater magnitude.
The total lateral surface area
This is the area of the sides of the figure. In this case it will be the sum of the three rectangles.
(13) * (14) + (13) * (14) + (14) * (10) = 504yd ^ 2
the total surface area.
This is the surface area of the whole figure. In this case there are three rectangles and two triangles.
(13) * (14) + (13) * (14) + (14) * (10) + (1/2) * (10) * (12) + (1/2) * (10) * (12 ) = 624 yd ^ 2
the answer is
total lateral surface area: 504yd ^ 2
total surface area: 624 yd ^ 2
Answer:
288x+576
Step-by-step explanation:
A=12×h(b1+b2)
A=12×12(x+1+x+3)
A=144(2x+4)
A=288x+576
Pare a.) $70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.
Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.
Four plus the absolute value of twenty-seven minus ten
