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3 years ago

Find the Solution of the equation -2x + 7 = 7

Mathematics

1 answer:

Basile [38]3 years ago

8 0

Answer:

x = 0

Step-by-step explanation:

-2 x 0 + 7 = 7

-2 x 0 = 0

0 + 7 = 7

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Y= Pls help solve for

miss Akunina [59]

Answer:

$y=39\degree$

Step-by-step explanation:

The given triangle is a right angle triangle .

The known sides of the triangle that is opposite to angle y is 8 units while the side adjacent is 10 units.

The value of y can be calculated using the tangent ratio.

$\tan(y)=\frac{8}{10}$

We solve for y to get,

$y=arctan(\frac{4}{5})$

We evaluate to obtain,

$y=38.66$

$y=39\degree$ to the nearest degree

8 0

3 years ago

If x + 2 is the only factor of the polynomial P(x),then P(2) is:

Levart [38]

Answer:

The answer is R(2).

Step-by-step explanation:

hope this helped!

4 0

2 years ago

6000 is deposited into a fund at the annual rate of 9.5%. Find the time required for the investment to double if the interest is

Anna [14]

Answer: 7.58 years

Step-by-step explanation:

When it comes to finding out how long it will take for an investment to double, one can use the Rule of 72.

The Rule of 72 estimates the amount of time it will take to double an investment when you divide 72 by the interest rate:

= 72 / r

= 72 / 9.5

= 7.58 years

3 0

2 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

so the area is

$\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx$

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the $i$ -th subinterval are, respectively,

$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$

which is about 651.918, so that the area is approximately $651.918\pi\approx\boxed{2048}$ .

Compare this to actual value of the integral, which is closer to 1967.

4 0

3 years ago

9 2/3 - 5 2/3 :)))))

Vlad1618 [11]

29/3 - 17/3
15/3 is your answer, or 5

4 0

3 years ago