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2 years ago

Rational number between -1 and 1

Mathematics

1 answer:

Nonamiya [84]2 years ago

8 0

Answer:

$\dfrac{-1}{2}$

Step-by-step explanation:

We need to find ration numbers between -1 and 1.

Multiplying and dividing both -1 and 1 by 2.

$\dfrac{-1\times 2}{2}=\dfrac{-2}{2}$

and $\dfrac{1\times 2}{2}=\dfrac{2}{2}$

Now, the rational number between -2/2 and 2/2 is $\dfrac{-1}{2}$ .

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Given f(x) = -2x +12, find f(-3).

lapo4ka [179]

Answer:

Step-by-step explanation:

-2(-3)+12=18

4 0

3 years ago

There are 600 pages in a novel. Rui feng reads 150 pages of the novel on friday and 40% of the remaining pages on sunday express

nadya68 [22]

Step-by-step explanation:

percentage

current number/total number * 100

150/400*100 is 37.5%

5 0

3 years ago

camp oak gets 32 boxes of orange juice and 56 boxes of apple juice each self in the cupboard can hold 8 boxes of juice what is

Flura [38]

32 boxes of oj + 56 boxes of aj = 90 boxes of juice
If a self can only hold 8 boxes of juice, then you need to divide 90 by 8.
90/8 = 11.25
This means that they need at least 12 shelves for all the Juice boxes.

7 0

3 years ago

Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?

kari74 [83]

We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

We know that a geometric sequence is in form $a_n=a_1(r)^{n-1}$ , where,

$a_n$ = nth term of sequence,

$a_1$ = 1st term of sequence,

r = Common ratio,

n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

$a_n=1\cdot (7)^{n-1}$

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where $n\geq 1$ .

4 0

3 years ago

I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be

Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

$P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}$

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: $g'(-1)\,(1)$ since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: $g'(-1)= 7$ as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0

3 years ago

Rational number between -1 and 1​

Rational number between -1 and 1