3(2a-5) = 12-7a
6a-15=12-7a
6a+7a=12+15
13a= 27
27=3c-3(6-2c)
27=3c-18+6c
27+18=3c+6c
45=9c
C=45/9
C=5
6c-8-2c=-16
6c-2c=-16+8
4c=-8
C=-8/4
C=-2
Answer:
A, C, D, E
Step-by-step explanation:
According to the rational root theorem, any rational roots will be of the form ...
±(divisor of the constant)/(divisor of the leading coefficient)
The constant is 8, and its divisors are 1, 2, 4, 8.
The leading coefficient is 6, and its divisors are 1, 2, 3, 6.
So, no rational root will have 3 in the numerator, eliminating choices B and F. The remaining choices are possible rational roots:
Answer: There were 40 euros in the drawer at the beginning.
Step-by-step explanation:
When we subtract 6 from 16, we get 10 more ice-creams were sold.
Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.
i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros
Selling price of 6 ice-creams = 6 x 5 = 30 euros
Money in the drawer at the beginning = 70-30 = 40 euros
Hence, there were 40 euros in the drawer at the beginning.
F(x) = 5(-3x) ^2 - (-3x) + 1
f(x) = -8x ^2 + 3x + 1
f(x) = -8x ^3 + 3x
Answer:
22
Explanation:
I-d-k a educated-guess
