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Molodets [167]
3 years ago
8

Name the compound TiBr3

Chemistry
1 answer:
mixer [17]3 years ago
5 0

Answer:

Titanium (III) bromide

Explanation:

As it is an ionic compound we write the valency for transition elements, and that means here that titanium loses three electrons to become +3 (Ti

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How many moles are in 3.57 x 10 32<br> particles Ca?
valentina_108 [34]

Answer:

\boxed {\boxed {\sf 592,826,303.6 \ moles \ of \ Ca }}

Explanation:

To convert from moles to particles, we must Avogadro's Number.

6.022*10^{23}

This number tells us the number of particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, it is the particles of calcium in 1 mole of calcium.

6.022*10^{23} \ particles \ Ca / mole \ Ca

We can use Avogadro's Number as a ratio or fraction.

\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}

Multiply this by the given number of particles (3.57*10³²).

3.57*10^{32} \ particles \ Ca*\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}

Flip the fraction so the particles of calcium will cancel out.

3.57*10^{32} \ particles \ Ca*\frac{1 \ mol \ Ca}{6.022 *10^{23} \ particles \ Ca}

3.57*10^{32} *\frac{1 \ mol \ Ca}{6.022 *10^{23} }

\frac{3.57*10^{32} \ mol \ Ca}{6.022 *10^{23} }

592826303.6 \ mol \ Ca

There are <u>592,826,303.6 moles</u> of calcium in 3.57*10³² particles of calcium.

8 0
3 years ago
How many grams of O₂ can be prepared from the thermal decomposition of 4.27 kg of HgO? Name and calculate the mass (in kg) of th
babymother [125]

Mass of Oxygen is: 0.784gm

Potassium chlorate is KClO3 and the decomposition looks like this...

2KClO3 ==> 2KCl + 3O2

4.50 g KClO3 x 1 mole/122.55 g = 0.0367 moles

0.0367 moles KClO3 x 3 moles O2/2 moles KClO3 = 0.0245 moles O2 (see mole ratio in balanced equation)

mass of O2 = 0.0245 moles O2 x 32 g/mole = 0.784 g O2 formed

<h3>What is the pressure of a mixture of CO2 and KR?</h3>

A mixture of CO2 and Kr weighs 37.0 g and exerts a pressure of 0.737 atm in its container. is expensive, you wish to recover it from the mixture.

<h3>How much oxygen is created when one mole of potassium chlorate breaks down?</h3>

in the reaction 2K C lO3 2K C l + 3O2 K C lO3? This demonstrates that 3 moles of oxygen gas are created for every 2 moles of degraded potassium chlorate.

<h3>How is high pressure liquid CO2 produced?</h3>

High pressure liquid CO 2 is produced by compressing the gaseous CO 2 in multistage compressors to pressures in the neighbourhood of 69 bar (1000,76 psi) pressure, then cooling it to around 18 °C (64,4 °F). It is customarily filled into specially constructed steel cylinders.

Learn more about decomposition HgO:

brainly.com/question/15066243

#SPJ4

5 0
2 years ago
What is 1 item that is a compound?<br><br>Give an example of how the 1 item is a compound :D
spayn [35]

Water

Water is a compound because it is made from more than one kind of element (oxygen and hydrogen).

3 0
4 years ago
What is the mode of action of most antifungal drugs?
Goshia [24]

Inhibition of protein synthesis is the mode of action done by most antifungal drugs.

<h3>What is the mode of action of antifungal drugs?</h3>

Antifungals drugs inhibit the synthesis of ergosterol the main fungal sterol, polyenes which interact with fungal membrane sterols and 5-fluorocytosine inhibits macromolecular synthesis.

So we can conclude that inhibition of protein synthesis is the mode of action done by most antifungal drugs.

Learn more about drug here: brainly.com/question/26254731

3 0
2 years ago
What is the energy required to change a spherical drop of water to five smaller spherical drops of equal size? At room temperatu
pav-90 [236]
T<span>his is a straightforward question related to the surface energy of the droplet. </span>

<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>

<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>

<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>

<span>The five smaller droplets need to have the same volume as the original. Therefore </span>

<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>

<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>

<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>

<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>

<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
3 0
3 years ago
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