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Bad White [126]
3 years ago
9

If 16.00 g of O₂ reacts with 80.00 g NO, what is the excess reactant? * A.O₂ B.NO

Chemistry
1 answer:
Fed [463]3 years ago
8 0

Answer:

  B. NO

Explanation:

In each mole of NO, the weight of the oxygen is 16.00 g; the weight of the nitrogen is 14.01 g. Then in 80 g of NO, we have 42.65 g of oxygen and 37.35 g of nitrogen.

__

In each mole of NO₂, the weight of the oxygen is 2(16.00) = 32 g. The weight of the nitrogen is 1(14.01) = 14.01 g.

From the available oxygen, we can produce ...

 (42.65 g +16 g)/(32.00 g/mol) = 1.83 mol of NO₂

From the available nitrogen, we can produce ...

 (37.35 g)/(14.01 g/mol) = 2.67 mol of NO₂

Clearly, the reaction is limited by the amount of available oxygen.

NO is the excess reactant.

__

Read more at ...

brainly.com/question/16500145

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