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Mnenie [13.5K]
3 years ago
5

Which of the following pairings usually forms molecular compounds?

Chemistry
1 answer:
nikdorinn [45]3 years ago
7 0

A nonmetal and a nonmetal will make molecular compounds like H2O and CO2

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Which reaction occurs spontaneously?
WARRIOR [948]

The answer is: (1) Cl2(g) + 2NaBr(aq)-->Br2(l) + 2NaCl(aq).

In this chemical reaction chlorine change oxidation number from 0 to -1 (reduction) and bromine change oxidation number from -1 to 0 (oxidation).

Chlorine is stronger oxidation reagent than bromine.

In VIIA or group 17 (halogen elements) there are six elements: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At) and tennessin(Ts).

They have high electronegativity because they have seven valence electrons in their outermost energy level, so they can gain an electron to have the octet rule.  

Going down in the group, element are weaker oxidazing reagent and less reactive.

Electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

4 0
3 years ago
Read 2 more answers
The structure of 3-propylpentane is best described as
victus00 [196]
The correct answer is b
7 0
3 years ago
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On the graph, indicate the average kinetic energy of the population at T1 and T2.
kondaur [170]

Answer:

The average KE of the two graphs is where they intersect. Another name for temperature is kinetic energy because temperature is how fast atoms are moving and bumping into each other ( more bumping means higher temperature ).

6 0
3 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0053 and Ka2 is determined
Savatey [412]

Answer:

Ka3 for the triprotic acid is 7.69*10^-11

Explanation:

Step 1: Data given

Ka1 = 0.0053

Ka2 = 1.5 * 10^-7

pH at the second equivalence point = 8.469

Step 2: Calculate Ka3

pKa = -log (Ka2) = 6.824

The pH at the second equivalence point (8.469) will be the average of pKa2  and pKa3. So,

8.469 = (6.824 + pKa3) / 2

pKa3 = 10.114

Ka3 = 10^-10.114 = 7.69*10^-11

Ka3 for the triprotic acid is 7.69*10^-11

6 0
3 years ago
How can an abiotic factor affect a biotic factor
xenn [34]
Biotic and abiotic factors are the environmental conditions that the organisms have to face to live in a specified environment.

-Abiotic factors-
Abiotic factors are the physical and chemical conditions of an environment. For example : heat, salinity, pressure, light, wind, pH ...

-Biotic factors-
Biotic factors are all the biological conditions of an environment for a specie/taxa. It can include prey and predator abundance, available food amount, available space, intra and interspecific competition...

The development of organims is under the control of abiotic factors. Some are adapted to heat, cold etc ... The abiotic factors will define which organisms are able or not to live in a specified place.

The living organisms will constitute the biotic factors, which define if and how can an organism live in a specified environment.
So, the abiotic factors are controling the biotic factors of an environment.

Hope it helps you !
4 0
3 years ago
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