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nevsk [136]
2 years ago
11

Tom pushes on a 50-kilogram box with a force of 25 newtons. Assuming the surface on which the box moves is frictionless, at what

rate does the box accelerate?
Chemistry
1 answer:
zhannawk [14.2K]2 years ago
3 0

Assuming the surface on which the box moves is frictionless, the rate at which the box accelerate is equal to 0.5 m/s^2.

<u>Given the following data:</u>

  • Mass of box = 50 kilogram
  • Force = 25 newtons.

To determine the rate at which the box accelerate, assuming the surface on which the box moves is frictionless:

Mathematically, Newton's Second Law of Motion is given by the formula;

Force = mass \times acceleration

Making acceleration the subject of formula, we have:

Acceleration =\frac{Force}{mass}

Substituting the given parameters into the formula, we have;

Acceleration = \frac{25}{50}

Acceleration = 0.5 m/s^2

Read more on Newton's Law of Motion here: brainly.com/question/1121817

You might be interested in
How many moles are equal to 1.4 x 10^24 atoms of aluminum
Svetlanka [38]

Answer: 2.3 moles

Explanation:

Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms

So if 1 mole of Aluminum = 6.02 x 10^23 atoms

Then, Z moles = 1.4 x 10^24 atoms

To get the value of Z, we cross multiply:

1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)

1.4 x 10^24 atoms = Z x (6.02 x 10^23)

Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)

Z =2.3 moles

Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.

4 0
3 years ago
OHC-CH2-CH2-CH2-CHO<br><br> What is the IUPAC name of this compound ?
Rufina [12.5K]

Answer:

Pentan_1,5_di-al

Explanation:

OHC-CH₂-CH₂-CH₂-CHO

This is Pentan_1,5_di-al

If we break this compound, we will observe that there is presence aldehyde group and hence the functional group "al". This aldehyde is bonded to carbon 1 and carbon 5 respectively.

Also the pentan is due to presence of 5 carbon atoms.

Therefore, the IUPAC name of this compound (OHC-CH₂-CH₂-CH₂-CHO) is  Pentan_1,5_di-al

5 0
3 years ago
If the pOH of a solution is 9.1, what is the concentration of OH- ions in that solution?
Amiraneli [1.4K]

Answer:

7.9432*10^-10 or 10^-9.1

Explanation:

pOH=-log[OH]

4 0
2 years ago
According to the article, HOW has the discovery of
Irina-Kira [14]

Answer:a

Explanation:

i think so cs i read the ariticle

8 0
3 years ago
Need asap! Step-by-step pls: Determine the empirical formula: 32.37% Na, 22.58% S, 45.05% O​
Ludmilka [50]

1) divide each percentage by the relative atomic mass of the element

2) divide all results by the smallest number

3)multiply by a whole number to get the simplest whole number ratio (if necessary)

that is to say:

Na                                   S                            O

32.37÷23                 22.58÷32                45.05÷16

= 1.407                       = 0.7056               = 2.816       (to 4 significant figures)

the smallest number here is 0.7056 so:

1.407÷0.7056        0.7056÷0.7056       2.816÷0.7056

=1.99 approx.2                   = 1                   3.99 approx. 4

here there is no need to carry out step 3 as ratio obtained is already a simplest whole number  ratio

so empirical formula is: Na₂SO₄

8 0
3 years ago
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