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Nana76 [90]
2 years ago
9

Use the DESMOS graphing calculator to find the solution to the system.

Mathematics
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer:

Can you be more specific of what you are looking for please? i just entered it into the calc but what are you looking for as the answer?

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Find a primitivism root of 6
avanturin [10]

Answer:



6, 5, 47, 5, 103, 5, 167, 5

8 0
2 years ago
Bananas are $.59 a pound what is the constant of proportionality
hichkok12 [17]
The constant proportionality is the proportionality of 59. Because it is the price, you just move the decimal point two places over to the left.
If you do this correctly you will get .59
4 0
3 years ago
Which tipe of this method???​
Hoochie [10]

Answer:

It appears to be substitution

Step-by-step explanation:

I think you are talking about system of equations

6 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
Use the following function rule to find f(12). f(x)=10x-4, f(12)=
DaniilM [7]

f(x)=10x-4, f(12)= 116

4 0
3 years ago
Read 2 more answers
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