A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159
The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4
Answer:
Equilateral
Step-by-step explanation:
Answer:
1.25*10^-4
2*10^-4
3.25*10^-10
Step-by-step explanation:
Esay, first what you have to do us move -6 to the right side and now you will have 3y=-3x+6, what you want to do next is to divide 3y by both sides and your final answer is y=-x+2, hope this helps.