All categories

3 years ago

Which number produces a rational number when multiplied by 0.5?

1 answer:

4 0

If the number begins by being rational, multiplying by 0.5 will not change whether or not it is rational. It will remain rational.

That would include any even number 12 * 0.5 = 6

12 started out as rational, so the answer is rational (6)

Any odd number is also rational

23 * 0.5 = 11.5

23 and 11.5 are both rational.

3.636363636 ... is rational so when multiplied by 0.5 the result will be rational.

1.818181818....

So if we start with something irrational like pi

then pi * 0.5 is not rational.

If you have choices, please list them.

You might be interested in

Simplify X+^2+8x+7/X^2-1

denis23 [38]

Answer:try 43

Step-by-step explanation:

3 0

3 years ago

Please help and explain

lakkis [162]

Answer:

look at the picture I sent

4 0

3 years ago

Please help I'll give brainliest! This is number 6

seraphim [82]

Answer:

< 1 = 125 degrees

< 2 = 55 degrees

< 3 = 125 degrees

< 4 = 55 degrees

< 5 = 125 degrees

< 6 = 55 degrees

< 7 = 125 degrees (given)

< 8 = 55 degrees

Step-by-step explanation:

1 and 3 are equal because they are vertical angles, therefore proving their congruence.

7 and 1 are equal because they're alternate exterior angles, which are congruent.

2 and 4 are vertical, which is congruent.

5 and 7 are vertical.

6 and 8 are vertical.

7 0

3 years ago

At The Green House of Salad, you get a

Leto [7]

Answer:

30 salads

Step-by-step explanation:

6 0

3 years ago

Will rate7 you brainliest

Vilka [71]

Answer:

$\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }$

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

$\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)$

$\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)$

$\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)$

$\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)$

Now, let's compute the product.

$\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}$

So the correct answer is the first one.

Thank you.

7 0

3 years ago