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Semmy [17]
2 years ago
8

A child got 16.67/20 on a test. what is their grade in percent form?​

Mathematics
1 answer:
solong [7]2 years ago
3 0

Answer:

83.4% or 83%

Step-by-step explanation:

when trying to find a percent, divide the numerator (# of correct answers) by the denominator (# of total questions possible to get correct)

Which would be 16.67 divided by 20 which equals .8335. Move the decimal point over two placements which would be 83.35. I rounded it up to 83.4. If trying to find a whole number not a decimal it would be 84%. Depending on the grading scale, it would be a B.

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How can I solve these problems​
Anuta_ua [19.1K]
Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know

4 0
3 years ago
determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).
ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is

(x - 8)² + (y + 6)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (8, - 6 ) and (x₂, y₂ ) = (5, - 2 )

r = \sqrt{(5-8)^2+(-2-(-6))^2}

  = \sqrt{(-3)^2+(-2+6)^2}

  = \sqrt{9+4^2}

  = \sqrt{9+16}

   = \sqrt{25}

   = 5

Then equation of circle is

(x - 8)² + (y + 6)² = 5² , that is

(x - 8)² + (y + 6)² = 25

6 0
2 years ago
Please solve this law of indices​
PilotLPTM [1.2K]

4√36^-1 = 36^-1/4

36^3/4 • 36^-1/4

=36^2/4

or √36 = 6

5 0
2 years ago
Read 2 more answers
Select all the equations that have x = 0.9 as a solution
Solnce55 [7]
C and d are going to be the answers to your question. >-< :)
7 0
3 years ago
What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?
Ahat [919]
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
\boxed{y = 6}

Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

6 0
3 years ago
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