$= > \frac{ \sqrt{96} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12 \times 8} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12} \times \sqrt{8} }{ \sqrt{8} } \\ \\ = > \sqrt{12} \\ \\ = > \sqrt{4 \times 3} \\ \\ = > \sqrt{2 \times 2 \times 3} \\ \\ = > 2 \sqrt{3}$

3 0

2 years ago

Please help ASAP !!!! Will mark Brainliest

AfilCa [17]

Only multiplication and division don't change the ratio that made the order pairs in the bigger picture the triangle. Only one is not congruent. I'm about 90% sure I got it correct.

3 0

2 years ago

Find x. Question 1 options: 6 3 9 12

Eduardwww [97]

Answer:18

Step-by-step explanation:

3 0

2 years ago