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3 years ago

Write the factors of 100 the ADD up to 25

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

100 50 25 10 4 2 1 are the factors of 100

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Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari

Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

<u><em>Let X = waiting time for a car to pass by on a country road</em></u>

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as 35 minutes that means $\lambda = \frac{1}{35}$ .

So, X ~ Exp( $\lambda = \frac{1}{35}$ )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

$F(x) = P(X \leq x) = 1 - e^{-\lambda x}$ , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X $\leq$ 37 min)

P(X $\leq$ 37 min) = $1 - e^{-\frac{1}{35} \times 37}$ {Using CDF}

= 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

4 0

3 years ago

SOMEONE PLEASE HELP!!!!!!!!!!!!!!!!!!1

UkoKoshka [18]

the answer is 5 if you need an explanation ask for it in the comments

8 0

3 years ago

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Jill is considering a 7/23 balloon mortgage with an interest rate of 3.5% to

abruzzese [7]

Answer: A. $1189.97

Step-by-step explanation:

8 0

3 years ago

What is 2/3 of $300?

wel

Well one third is 100
so two thirds must be 200

3 0

4 years ago

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The bending of a bean varies directly as its mas. A beam is bent 20mm by a mass 0f 40kg. how much will the beam bend with a mass

Naddik [55]

Answer:

The beam will bend by 50 mm with a mass of 100kg?

Step-by-step explanation:

The first step in solving the problem of direct variation is setting up the relation mathematically.

We can do this as follows:

The bending of the beam varies directly as its mass.

$20 \alpha 40kg$

$\alpha$ here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k

$20 = k \times 40$

k = 20 /40 = 0.5

We can now use this to find the distance the beam will bend with a mass of 100kg?

This will be

$Bending = 0.5 \times 100 =50mm$

There fore, the beam will bend by 50 mm with a mass of 100kg?

6 0

4 years ago

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