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VladimirAG [237]
3 years ago
14

X2 + 2y ÷ w + 3z for w = 2, x = 5, y = 8, and z = 3?

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Step-by-step explanation:

w = 2

x = 5

y = 8

z = 3

= x² + 2y ÷ w + 3z

= (5)² + 2(8) ÷ (2) + 3(3)

= 25 + 16 ÷ 2 + 9

= 25 + 8 + 9

= 42

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If the total is 31 dogs how many dogs Carlos walked?
Snowcat [4.5K]

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Please help <br> thank you
Scrat [10]
Question 1:

Use the Pythagorean theorem.

If c^2\ \textless \ a^2+b^2, then the angle is acute.
If c^2=a^2+b^2, then the angle is right.
If c^2\ \textgreater \ a^2+b^2, then the angle is obtuse.

a=18
b=80
c=81

c^2=6561
a^2+b^2=324+6400=6724

\boxed {c^2\ \textless \ a^2+b^2}

Thus, the angle is acute.

Question 2:

Take the square root of the area to get the side length.

\sqrt{200} = \sqrt{100*2} =10 \sqrt{2}

That's the side length. Since we have a 45-45-90 right triangle if we divide the square across its diagonal, we just multiply the side length by the square root of 2 in order to get the diagonal length.

10 \sqrt{2} *  \sqrt{2}
=20

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7 0
4 years ago
Select the correct answer from each drop-down menu
Yakvenalex [24]

Answer:

First row. = -393 74 287

Second row = 471. 162 91

Third row =251 222 - 349

Step-by-step explanation:

For the first row

Cofactor of 12= (-8*15)-(21*13)

= -120-273

= -393

Cofactor of 23 = (11*15)-(7*13)

= 165-91

= 74

Cofactor of -6 = (11*21)-(-7*8)

= 231+56

= 287

For the second row

Cofactor of 11 = (23*15)-(21*-6)

= 345+126

= 471

Cofactor of -8 = (12*15)-(7*-6)

= 120 + 42

= 162

Cofactor of 13 (12*21)-(23*7)

= 252-161

= 91

For third row

Cofactor of 7= (23*13)-(-8*-6)

= 299-48

= 251

Cofactor of 21 = (12*13)-(11*-6)

= 156+66

=222

Cofactor of 15 = (12*-8)-(11*23)

= -96 - 253

=- 349

8 0
3 years ago
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