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AURORKA [14]
3 years ago
15

To prevent long page load times for pages containing images, it is best to use a compressed file format such as JPG, as well as

appropriate image dimensions and
resolution.
magnification.
orientation.
colors.
Computers and Technology
1 answer:
valkas [14]3 years ago
7 0

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The given options to this question are:

  1. resolution.
  2. magnification.
  3. orientation.
  4. colors.

The correct option to this question is 1. i.e.

Resolution.

The resolution of an image determines how many pixels per inch an image contains. Image having a higher resolution takes long page load times for a page and lower resolution takes less page load time. So, to prevent long page load times for pages containing images, it is best to use compressed file formation as well as appropriate image dimension and resolution.

While other options are not correct because:

Magnification, orientation, and color does not affect the page load time. Page load time for images only affected by the dimension and resolution of the images.

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Janice usually works on a particular workbook that contains all business related data. She decides to keep a backup of all the d
quester [9]

The answer is to use the Ctrl and C keys on the keyboard to copy content from one workbook to another.

The Ctrl and C key is the standard combination keys on the keyboard that is used to copy any selected text or objects while in a user interface environment. Janice is required to press the C key while holding down the Ctrl key to copy all the content to the new workbook.

Another way of doing it is to make sure that both source and target workbooks are open. Navigate the sheets you want to copy or move in the source workbook. Click the Home tab and select then format dropdown in the Cells group. Select move or copy sheet option in the Organize sheet option. Choose the target workbook from the To Book dropdown and click OK.

6 0
4 years ago
Read 2 more answers
if you want to present slides to fellow students and co-workers which productivity software should you use to create them?
ladessa [460]

Answer:

Microsoft PowerPoint.

Explanation:

Because, it is industry standard and widely recognized and used in world.

8 0
3 years ago
The iteration variable begins counting with which number?<br> O 0<br> O 1<br> O 10<br> O 0 or 1
bonufazy [111]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The iteration variable begins counting with 0 or 1.

As you know the iteration mostly done in the looping. For example, for loop and foreach loop and while loop, etc.

It depends upon you that from where you can begin the counting. You can begin counting either from zero or from one.

For example: this program counts 0 to 9.

<em>int total=0;</em>

<em>for(int i=0; i>10;i++)</em>

<em>{</em>

<em>total = total+i;</em>

<em>}</em>

Let's suppose, if you want to begin counting from 1, then the loop should look like below:

<em>int total=0;</em>

<em>for(int i=1; i>10;i++)</em>

<em>{</em>

<em>total = total+i;</em>

<em>}</em>

7 0
3 years ago
Stacy's job involves direct coordination and communication with end users. Which option describes her job role?
masha68 [24]

Answer:

Stacy works as a Customer Service Representative.

Explanation:

Since Stacy uses coordination and communication, she would best fit the criteria for costumer service. A Customer Service Representative (CSR) helps customers out with questions about a business, including directions, finances, and other benefits of her company.

3 0
3 years ago
2. Write a program that calls creates an ArrayList of integer and calls the method minToFront described below. Print out the lis
Novosadov [1.4K]

Answer:

import java.util.ArrayList;

public class MinToFront {

   public static void minToFront(ArrayList < Integer > list){

       int miniIndex = 0;

       for(int j=1; j<list.size(); j++){

          if(list.get(miniIndex) > list.get(j))

               miniIndex = j;

      }

      // moving min to front

       int min = list.get(miniIndex);

       list.remove(miniIndex);

       list.add(0, min);

  }

  public static void main(String[] args) {

       ArrayList<Integer> list = new ArrayList<>();

      list.add(4);   //value store in list

      list.add(7);   //value store in list

      list.add(9);  //value store in list

      list.add(2);  //value store in list

      list.add(7);  //value store in list

      list.add(7);  //value store in list

      list.add(5);  //value store in list

       

      list.add(3);  //value store in list

       

      list.add(5);  //value store in list

       

      list.add(1);  //value store in list

       

      list.add(7);  //value store in list

       

      list.add(8);  //value store in list

       

      list.add(6);  //value store in list

       

      list.add(7);  //value store in list

       

      System.out.println(list);

      minToFront(list);

      System.out.println(list);

  }

}

Output:

[1, 4, 7, 9, 2, 7, 7, 5, 3, 5, 7, 8, 6, 7]

Explanation:

Firstly,we define a method minToFront(), than set an integer variable "miniIndex" to 0, than set a for loop and apply the following condition and inside the loop we apply the if condition, set an integer variable "min" in which we store the value and than we set the following list [4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7], after that print the list and than print an output.

3 0
3 years ago
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