Hello please help on these 3 questions with the information at the top please help it's for marks

While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

AVprozaik [17]

Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

$p_v =P(Z>0.0057)=0.4977$

The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

4 0

4 years ago

It is not C I will give brainliesy

Illusion [34]

The answer is B : -5/2

8 0

3 years ago

Read 2 more answers

2n+(7n+8)= what is the missing coefficient

Taya2010 [7]

Assuming that you were to simplify this, you'd get 2n + 7n + 8 = 9n + 8.

6 0

3 years ago

Simplify by combining like terms 6a + 3b + a + 2

IrinaK [193]

Answer:

$7a+3b+2$

Step-by-step explanation:

$6a+3b+a+2$

Use commutative property of addition $x+y=y+x$

$6a+3b+a+2=6a+(a+3b)+2$

use associative property of addition $x+(y+2)=(x+y)+2$

$6a+(a+3b)+2=(6a+a)+3b+2\\=7a+3b+2$

Hence $6a+3b+a+2=7a+3b+2$

6 0

3 years ago

Help guys but thanks to your help I got a 100 on my homework yesterday .

Alexeev081 [22]

Easy peasy
1.
d=number of dudes
l=number of ladies
total is 55 so
d+l=55

total cost is 75 so
2d+l=75
multiply first eeuqaiton by -1 and add to second

2d+l=75
<u>-d-l=-55 +</u>
d+0=20

d=20
sub
d+l=55
20+l=55
l=35
35 ladies

2.
ratio and proportion
$87 is to 8 as is $x is to 5
87/8=x/5
times both sides by 5
435/8=x
use calculator
54.375=x
round
$54.38 recieved

3.
around the edge
means perimiter
disregard how deep the pool is

60 feet long
x wide
P=2(L+W)
P=220
220=2(60+x)
divide 2
110=60+x
minus 60 both sides
50=x
it has to be 50 feet wide

4. monthly over 5 years
1 year=12 months
12 times 5=60 months
12381/60=206.35 per month
$206.35

5.
total-food-gas-utilities=left
1624-256-125-150=1093 left
you should be able to do this one no problem
$1093 let

1. 35 ladies
2. $54.38
3. 50 feet
4. $206.35
5. $1093

3 0

3 years ago