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Evgen [1.6K]
3 years ago
7

Ill give brainlist if someone can help me with this question

Mathematics
1 answer:
inna [77]3 years ago
3 0

Answer:

m = 1 and b = 5/7

Step-by-step explanation:

Take two of the points. The first two. (7, 5) and (8, 6).

We can find the slope using:

y2-y1/x2-x1

We can sub in the values:

6-5/8-7 = 1/1 = 1

So the slope is 1

now, putting this into y=mx+b, and using one of the coordinates from earlier, we can solve for b:

5 = (1)(7) + b

b = 5/7

Therefore, m = 1 and b = 5/7

Hope this helps!

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Which shows the dimensions of two rectangular prisms that have volumes of 240 ft3 but different surface areas?
bulgar [2K]
Calculate the volume and surface areas of both rectangular prisms for each option.

A:

Rectangular Prism #1
\sf V=lwh
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\sf A=2((8)(5)+(6)(5)+(6)(8))
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Rectangular Prism #2
\sf V=lwh
\sf V=(5)(6)(8)=240~ft^3

\sf A=2((5)(6)+(8)(6)+(8)(5))
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This is incorrect, they have the same volume of 240 cubic feet and the same surface areas.

B:

Rectangular Prism #1
\sf V=lwh
\sf V=(8)(5)(6)=240~ft^3

\sf A=2(wl+hl+hw)
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Rectangular Prism #2
\sf V=lwh
\sf V=(10)(8)(3)=240~ft^3

\sf A=2(wl+hl+hw)
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\boxed{\sf Correct~Answer}: Both have the same volume of 240 cubic feet, but different surface areas.

C:

Rectangular Prism #1
\sf V=lwh
\sf V=(15)(8)(2)=240~ft^3

\sf A=2(wl+hl+hw)
\sf A=2((15)(8)+(2)(8)+(2)(15))
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Rectangular Prism #2
\sf V=lwh
\sf V=(6)(4)(15)=360~ft^3

\sf A=2(wl+hl+hw)
\sf A=2((6)(4)+(15)(4)+(15)(6))
\sf A=348~ft^2

This is incorrect, they have different surface areas, but only Rectangle #1 has a volume of 240 cubic feet.

D:

Rectangular Prism #1
\sf V=lwh
\sf V=(12)(6)(5)=360~ft^3

\sf A=2(wl+hl+hw)
\sf A=2((12)(6)+(5)(6)+(5)(12))
\sf A=324~ft^2

Rectangular Prism #2
\sf V=lwh
\sf V=(8)(10)(3)=240~ft^3

\sf A=2(wl+hl+hw)
\sf A=2((8)(10)+(3)(10)+(3)(8))
\sf A=268~ft^2

This is incorrect, they both have different surface areas but only Rectangle #2 has a volume of 240 cubic feet.
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Answer:

First part = 2.

Time to land = 6 seconds.

Step-by-step explanation:

The object is at h = 0 when it land so

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