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Umnica [9.8K]
2 years ago
12

Is 7.6 repeating greater than 55 squared

Mathematics
1 answer:
max2010maxim [7]2 years ago
4 0
7.6 is greater<span> than 55 squared</span>
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Plz do number 4. 5th grade math​
77julia77 [94]

Answer:

your answer would be 78

Step-by-step explanation:

     78

9/702

 - 63

_____

      72

     - 72

_______

 0

4 0
2 years ago
Read 2 more answers
Kentucky teens which one is the best completes the statement or answers the question
vampirchik [111]

i’m not from kentucky but it’s A

lmk if you need me to explain

7 0
3 years ago
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
How can i get answers by factors of 256​
kobusy [5.1K]

Answer: Factor Pairs of 256

1 x 256 = 256.

2 x 128 = 256.

4 x 64 = 256.

8 x 32 = 256.

16 x 16 = 256.

Step-by-step explanation: These all equal up to 256

5 0
2 years ago
How do you solve this? please explain
Serggg [28]
Quick steps to solve this.

1. Lets square both. (X +Y)*2 = 7*7 
2. Then, X*2 + 2XY + Y*2 = 49
3. Since XY is given to 4, X*2 + 8 + Y*2 = 49
4. Move 8
5. X*2 + Y*2 = 49 - 8
6. X*2 + Y*2 = 41

The answer is "41"  Boom!
7 0
3 years ago
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