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Mariulka [41]
3 years ago
10

Can anyone help me pls

Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

9514 1404 393

Answer:

  A. some values (x = 4)

  B. all values

  C. no values

Step-by-step explanation:

If you subtract the right-side expression from both sides of an equation, so you get something of the form ...

  f(x) = 0

Then there are three possibilities:

  f(x) is some function of x . . . . "some values" make it true*

  f(x) = 0 . . . . "all values" make it true; the equation is an identity

  f(x) = constant (non-zero) . . . . "no values" of x will make it true

___

A: 3x = x +8

  3x -(x +8) = 0

  2x -8 = 0 . . . . . . . . true for "some" values of x, namely, x = 4

__

B: 5x -(x +x +x +x +x) = 0

  0 = 0 . . . . . . . . . . . true for "all" values of x

__

C: 2(x +5) -(2x +5) = 0

  2x + 10 -2x -5 = 0

  5 = 0 . . . . . . . . . . . true for "no values" of x (always FALSE)

_____

* The possibility exists that the function f(x) does not have 0 in its range. In that case, there are no real solutions for the equation. For example |x|+1 = 0 has no solutions. For expressions linear in x, there will always be a solution.

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Consider the curve defined by 2x2+3y2−4xy=36 2 x 2 + 3 y 2 − 4 x y = 36 .
8_murik_8 [283]

Answer:

Step-by-step explanation:

Given a curve defined by the function 2x²+3y²−4xy=36

The total differential of this function with respect to a variable x makes the function an implicit function because it contains two variables.

Differentiating both sides of the equation with respect to x we have:

4x+6ydy/dx-(4xd(y)/dx+{d(4x)/dx(y))} = 0

4x + 6ydy/dx -(4xdy/dx +4y) = 0

4x + 6ydy/dx - 4xdy/dx -4y = 0

Collecting like terms

4x-4y+6ydy/dx - 4xdy/dx = 0

4x-4y+(6y-4x)dy/dx = 0

4x-4y = -(6y-4x)dy/dx

4y-4x = (6y-4x)dy/dx

dy/dx = (4y-4x)/6y-4x

dy/dx = 2(2y-2x)/2(3y-2x)

dy/dx = 2y-2x/3y-2x proved!

5 0
3 years ago
Y = 2x + 5<br> Whats the answer for this? Whats the missing value <br> (2,__)
Anna35 [415]

Answer:

(-5/2, 5)

Step-by-step explanation:

Apply x-y intercepts theorem

(x,y)=(0,y) and (x,0).

then substitutes.

5 0
3 years ago
You earned $24 mowing lawns, which is 3/4 of the amount your
ELEN [110]
You and your friend made 13 each
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Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
Sonja [21]

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

7 0
3 years ago
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