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Mariulka [41]
2 years ago
10

Can anyone help me pls

Mathematics
1 answer:
Nikitich [7]2 years ago
3 0

9514 1404 393

Answer:

  A. some values (x = 4)

  B. all values

  C. no values

Step-by-step explanation:

If you subtract the right-side expression from both sides of an equation, so you get something of the form ...

  f(x) = 0

Then there are three possibilities:

  f(x) is some function of x . . . . "some values" make it true*

  f(x) = 0 . . . . "all values" make it true; the equation is an identity

  f(x) = constant (non-zero) . . . . "no values" of x will make it true

___

A: 3x = x +8

  3x -(x +8) = 0

  2x -8 = 0 . . . . . . . . true for "some" values of x, namely, x = 4

__

B: 5x -(x +x +x +x +x) = 0

  0 = 0 . . . . . . . . . . . true for "all" values of x

__

C: 2(x +5) -(2x +5) = 0

  2x + 10 -2x -5 = 0

  5 = 0 . . . . . . . . . . . true for "no values" of x (always FALSE)

_____

* The possibility exists that the function f(x) does not have 0 in its range. In that case, there are no real solutions for the equation. For example |x|+1 = 0 has no solutions. For expressions linear in x, there will always be a solution.

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chet needs to buy 4 work shirts,all costing the same amount .the total cost before chet appplies a $25 gift certificate can be n
Rashid [163]
So for this problem, let us use x as the cost before Chet would apply a $25 gift certificate. Based on the problem, we can see that the original cost of the product cannot be more than 75 which means that it can be equal to 75 or less than 75. We can actually express the inequality as x< or = 75 since we are looking for the cost before Chet applied the $25 gift certificate. This means that we do not need to add in the 25 yet since the question asks for the cost before the application of the discount. 
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Please help me I will choose brailiest
koban [17]

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similar; RYL by SAS similarity

Step-by-step explanation:

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In an Algebra II class with 135 students, the final exam scores have a mean of 72.3 and standard deviation 6.5. The exams on the
gregori [183]
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5

Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students

Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students

Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68

Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
4 0
3 years ago
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