1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Veseljchak [2.6K]
3 years ago
6

PLEASE HELP A B C D ???

Mathematics
1 answer:
Levart [38]3 years ago
4 0
The answer for this would be b
You might be interested in
Solve. Check your answer. <br> -3/z + 7/4z = 5/z-25
Anastaziya [24]

[~Answer~] (3.):

Hello there! I'm Avery, and I'm here to help you! I mostly believe the answer <em>Could be: (the answer is in the screenshot. I couldn't write it, so I typed it.)  </em>

<em>
</em>+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[~Answer Explanation~]:

1:

Combine multiplied terms into a single fraction

2:

Find common denominator

3:

Combine fractions with common denominator

4:

Multiply the numbers

5:

Re-order terms so constants are on the left

6:

Combine exponents

7:

Rearrange terms

8:

Find common denominator

9:

Combine fractions with common denominator

10:

Re-order terms so constants are on the left

11:

Rearrange terms

12:

Multiply all terms by the same value to eliminate fraction denominators

13:

Cancel multiplied terms that are in the denominator

14:

Distribute

15:

Move terms to the left side

16:

Distribute

17:

Subtract the numbers

18:

Rearrange terms

19:

Use the quadratic formula

20:

Simplify

21:

Separate the equations

22:

Solve

Answer:
z = \frac{-50 + 2\sqrt{681} }{7}

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[~Last Messages~]:

Okay, I really hope my answer is correct.

I am truly sorry if it's wrong :(

Have a great morning, afternoon, or night. <333

<u><em>[-!AveryIsSomeHowAlive!-}</em></u>

7 0
1 year ago
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term
elena55 [62]

Answer:

The no. of variations in sign is 3

Step-by-step explanation:

Variation in sign occurs when every single time a negative product is produced by a pair of consecutive terms.

Therefore, the determination of the number of changes in sign in the given sequence is must.

Therefore, we take the product of the pair of consecutive terms as:

1\times (-3) = - 3, variation in sign

(-3)\times 2 = - 6,  variation in sign

2\times 5 = 10,  no sign variation

5\times (- 4) = - 20,  variation in sign

- 4\times (-6) = 24, no sign variation

7 0
3 years ago
1 3/5 x 1 1/3 = 8/5 x 4/3
vodomira [7]
The answer is C. Hope this helps
3 0
3 years ago
Read 2 more answers
93 divided by 20 .................................................
DaniilM [7]

Answer:

4.65

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
a pair of sunglasses originally priced at $50 are now on sale for $31. What is the discount percentages?
scoray [572]

Answer:

They are discounted for 38% off.

5 0
3 years ago
Other questions:
  • A + (−5) = −12<br><br> What is a
    5·2 answers
  • Cases are normally sold full. There were three partially full cases that could be combined to make full cases. The cases were 11
    14·1 answer
  • Solve the following multiplication and division problems.
    15·1 answer
  • Answers to these! Need ASAP due tomorrow
    9·1 answer
  • 99 POINT PROJECT -- ACTUALLY DO IT, DONT TELL ME HOW! 99 POINTS.
    5·1 answer
  • In △ABC, m∠A=16°, m∠B=49°, and a=4. Find c to the nearest tenth.
    7·1 answer
  • The train takes 1 1/2 hours to get from Arno to Bentley. The train takes 5 times as long as that to get from Arno to Valdez how
    11·1 answer
  • Write an equation for which 0 is a solution​
    11·1 answer
  • Area codes are the first three digits of a 10-digit telephone number. The first digit of an area code cannot be 0 or 1.
    8·1 answer
  • Can someone help me on all of them I would appreciate it so much!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!