Answer:
A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).
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please mark brainliest
They are 1 and 3!
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Answer:
The correct answer is not shown in your picture. You must get a = 60.
Step-by-step explanation:
(1/2)a + (2/3)b = 50
b = 30
(1/2)a + (2/3)(30) = 50
(1/2)a + 20 = 50
(1/2)a + 20 - 20 = 50 - 20
(1/2)a = 30
2 * (1/2)a = 2 * 30
a = 60
The correct answer is not shown in your picture. You must get a = 60.
Check the picture below.
now, since we know what "f" is, let us use the CNT triangle with the small COR one.
Answer:
3 1/4 inches
Step-by-step explanation:
22 3/4 ÷ 7
21÷7=3
1 3/4 = 7/4
7/4= 1/4+1/4+1/4+1/4+1/4+1/4+1/4
3 1/4 inches
