In the parallelogram below, y = [?] 5y-20 2y+25 PLEASE HELP

Mathematics

1 answer:

Firdavs [7]3 years ago

8 0

If I remember correctly parallelograms have two pairs of parallel lines equal to each other

So 5y-20=2y+25

Solve for y

3y=45

y=15

The answer is y=15

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Find the equation of a line perpendicular to -x=4-y that passes through the point (-3,8)

Wewaii [24]

9514 1404 393

Answer:

y = -x +5

Step-by-step explanation:

Solving the given equation for y, we have ...

y = x +4

The slope of this line is the coefficient of x: 1. The slope of the perpendicular line will be the opposite reciprocal of this: -1/1 = -1. The y-intercept of the perpendicular line can be found from ...

b = y -mx = 8 -(-1)(-3) = 5

The perpendicular line has equation ...

y = -x +5