Answer:
256
Step-by-step explanation:
any number to the 0 power equals 1, so r^0 equals 1
then, you have (4(1))^4
4×1=4
4^4=256
Answer:
71
Step-by-step explanation:
[6x4(15/5)]+[2^2+(1x-5)]
BIDMAS (aka PEDMAS etc.)
Brackets
Indices
Division/Multiplication
Addition/Subtraction
[6 x 4(15/5)] + [2^2 + (1x-5)]
[6 x 4(3)] + [2^2 + (-5)]
[6 x 4(3)] + [4 + -5]
[6 x 12] + [4 + -5]
[72] + [4 + -5]
72 + [-1]
72 + - 1
72 - 1
71
If you’re solving for a... subtract the 8 to the other side so...
-4(a+3)- 3(2a-8) = 22.
Distribute the -4 and -3 into the parentheses (two negatives multiplied together is a positive)...
-4a-12-6a+24 = 22.
Add the constants and a’s together.
-10a + 12 = 22
Subtract 12 to the other side.
-10a = 10
Divide both sides by -10.
a = -1
Check and make sure that this answer works with the problem.
-4(-1+3)-3(-2-8)=22
-4(-2)-3(-10)=22.
-8+30=22.
22=22, the answer checks out
That's a hard one either c or d
