Please help !!!!ASAP!!!!Please answer the Picture below.

Mathematics

1 answer:

artcher [175]3 years ago

6 0

Answer:

Part A) shorter base = 6 yd longer base = 8 yd

Part B) C. 42 yds²

Step-by-step explanation:

Part A) The width and the length of the shorter side are the same, at 6 yds each. The longer base is 8 yds because there is a spot of 1 yd on both sides of the shorter side, making the longer side.

Part B) Find the area of the square first.

A = L x W

A = 6 x 6

A = 36 yds²

Next, find the area of a triangle and multiply the answer by 2 because there are two triangles.

A = 1/2bh

A = 1/2(1)(6)

A = 1/2(6)

A = 3(2)

A = 6 yds²

Add together all of the area measurements to find the area of the entire figure

36 + 6 = 42 yds²

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Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$