Question

Find the 16th term to the series PLEASEEE

Answer 1

Answer:

It is a geometric sequence.

$common \ ratio , r = \frac{12}{-4}=-3$

$a_n = a_1 \times r^{n-1} \\n = 16\\r = -3\\a_1 = -4\\a_{16 }= -4 \times (-3)^{15} = -4 \times 14348907 =57395628$