The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
<em>subtract 2 from both sides</em>
<em>divide both sides by (-4)</em>
Answer:1.625
Step-by-step explanation:you just divide 65 and 40
Answer: See below
Step-by-step explanation:
Same steps as the last question I answered
5) a ➤ x=-3
b ➤ y=7
6) x=-1
7) y=-4
Answer:
6,050,000
Step-by-step explanation:
